The question's notation (address/mask) for a wildcard match is unconventional for Junos. The only logical interpretation that yields two correct answers, as requested, is to treat the octets in the mask set to 255 as fixed and the octet set to 0 as a wildcard.

Given the base address 192.168.0.12 and the mask 255.255.0.255, the matching pattern requires the first octet to be 192, the second to be 168, and the fourth to be 12. The third octet can be any value. The resulting pattern is 192.168.X.12. Both 192.168.1.12 and 192.168.22.12 fit this pattern.

A. 192.168.1.21: The fourth octet (21) does not match the required value of 12 from the base address.

B. 192.168.0.1: The fourth octet (1) does not match the required value of 12 from the base address.

1. Juniper Networks TechLibrary - Junos OS Security Configuration Guide

"Understanding Wildcard Addresses": This official documentation clarifies the standard behavior of wildcard addresses in Junos OS. It states

"In a wildcard address

address bits are set to 0 to indicate a match and to 1 to indicate a 'don't care' bit." This shows that the question uses a non-standard

inverted logic for its mask. To achieve the result intended by the question (192.168.X.12)

the correct Junos wildcard mask would be 0.0.255.0.

URL: https://www.juniper.net/documentation/us/en/software/junos/security-policies/topics/concept/security-wildcard-address-understanding.html