Q: 2
There will be 100 concurrent users streaming video to their laptops. A 30/70 split between 2.4 Ghz
and 5 Ghz will be used. Roughly how many APs (rounded to the nearest whole number) are needed
based on client count?
Options
Discussion
Option C. seen a similar question on a practice set and it matches the Cisco docs method for wireless planning.
Don't think D is right, the trap here is rounding each band separately. Cisco docs suggest adding first then rounding, so C.
I'm thinking D makes sense if you round the APs per band individually first, then sum them up. So for 2.4 GHz (30 users / 15 per AP = 2), and for 5 GHz (70 users / 30 per AP = ~2.33, rounded to 2), so that gives you 4 total, but if both bands need their own APs, some guides say you need to count overlap or APs physically. Pretty sure it's D, unless I'm missing something obvious. Anyone else see it this way?
B not D. Saw this type in Meraki docs and official practice. Planners combine both bands then round, so C.
C/D? Similar question showed up on a recent practice, can't pick between them for this exact split.
Hard to say, C here, since the calculation (100 x 0.3 / 15) + (100 x 0.7 / 30) gives you about 5.66, and rounding to the nearest whole number gets you 6, but the Cisco docs example rounds each band first and sums (3 + 2 = 5). Still, most guides suggest combining before rounding, so I'd stick with C for this scenario. Pretty sure that's what they're looking for but open to other views.
C imo, is the one. Cisco wants you to sum first then just round at the end.
C, saw this asked the same way in practice exam reports recently.
Seen this split in Meraki capacity planning examples and the official guide-always combine both bands before rounding, so C.
No way it's D, C matches what I saw in some Cisco practice stuff. It's about combining both bands first and rounding at the end, not per band. Not 100% locked but pretty sure that's what they want here.
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