C. Compile-time error Here's why: Arithmetic Operation: First, the addition 5.7 + 3.2 is performed. Since both operands are floating-point numbers (doubles), the result will also be a double (8.9). Type Casting: Then, the result (8.9, a double) is cast to a byte using (byte). The problem arises because a byte has a much smaller range than a double. It can only store whole numbers between -128 and 127. Casting a value like 8.9 (which has a decimal part) to a byte leads to a loss of information. Java, to prevent unexpected behavior and data loss, throws a compile-time error in this situation. It's essentially saying that you're trying to fit a value that's too big for the target data type. Here's how you could fix the expression: Change the data type: If you specifically need a byte as the result, you can modify the expression to perform integer division (/) on the sum, discarding the decimal part: Java (byte) (int) (5.7 + 3.2) // This will result in (byte) 8 Use a wider data type: If you want to preserve the decimal part, consider using a data type like float or double that can handle decimals: Java (float) (5.7 + 3.2) // This will result in 8.9 (float) Remember to choose the data type that best suits your requirements to avoid data loss or unexpected behavior.